![]() We'd just have to remember to adjust the force acting at the CG according to the G-loading, in any case where it is other than one. Alternatively we could tackle the problem by computing the torques around the Center of Pressure rather than around the glider's CG- we'd get the same result, because we are free to choose any arbitrary pivot point in torque calculation problem. If the glider's CG is behind the Center of Pressure, then the hang strap must be connected to the glider ahead of the glider's CG. ![]() ![]() If glider's CG is ahead of the Center of Pressure, then the hang strap must be connected to the glider behind the glider's CG. Since the Net Aerodynamic Force vector- the vector sum of Lift and Drag- must be vertical in a wings-level steady-state glide, this means that the Center of Pressure must lie somewhere on a vertical line passing through the CG of the glider.Į) In the case where the hang strap is connected to the glider somewhat forward or aft of the CG of the glider, then the following must be true: the torque about the CG created by the G-loading on the pilot's body must exactly counteract the torque about the CG created by the Net Aerodynamic Force acting at the Center of Pressure. that the "hang strap" hangs straight down when the pilot is not pulling or pushing on the control bar.ĭ) In the simple case where the hang strap is connected to the glider right at the CG of the glider, or somewhere along a vertical line passing through the CG of the glider, then in order for the glider to be trimmed to fly hands-off, a line drawn through the Center of Pressure, parallel to the Net Aerodynamic Force vector generated by the glider, must pass through the CG of the glider. (Otherwise the glider would be unstable.)Ĭ) We'll assume that the drag on the pilot's body is negligible, i.e. In general, the Center of Pressure of the aircraft as a whole moves forward as angle-of-attack is decreased, and moves backwards as angle-of-attack is increased. Note however that the Center of Pressure is not fixed. We are not asking what will happen to the glider after a disturbance.ī) This answer will address the question in terms of Center of Pressure, not Aerodynamic Center, which simplifies things because we don't have to worry about a pitching moment coefficient.
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